Sanju Samson Hits 110-m Long Six During 58-Run Knock Against Zimbabwe In 5th T20I – WATCH

Sanju Samson was on fire for India in the fifth T20I against Zimbabwe on Sunday (July 14), which was played at the Harare Sports Club. In the final match of the India tour of Zimbabwe, the 29-year-old wicketkeeper-batter came out to bat at No. 4 for India and top-scored for the visitors by making 58 runs. During his 45-ball stay at the crease, the right-handed batter smacked one four and four sixes, and one of the sixes by him in the 12th over of Indian innings was so big that the ball travelled a distance of 110 m.

Samson was batting on 21 runs from 25 balls when he decided to play a big shot against Zimbabwe spinner Brandon Mavuta. The wicketkeeper-batter from Kerala hit the ball with such brute force that it travelled the distance of 110 m. The video of the massive hit by Samson is now going viral on the internet.

Samson, who was part of the Indian team that won the T20 World Cup 2024 last month, scored his second T20I fifty on Sunday to help India post a total of 167 runs for the loss of six wickets in 20 overs. He added 65 runs for the fourth wicket with Riyan Parag (22) who got a chance to play in the fifth T20I in place of Ruturaj Gaikwad.

After Parag’s dismissal, Samson added 30 runs for the fifth wicket with Shivam Dube (26) before being sent back to the pavilion by Blessing Muzarabani on the third ball of the 18th over.

India has already sealed the T20I series by winning the second, third, and fourth T20Is played in Harare on July 7, 10, and 13. In the fourth T20I played on Saturday, Jaiswal scored 93 runs from 53 balls and added 156 runs for the first wicket with Shubman Gill (58) to help India chase down the 153-run target in 15.2 overs and win the match by 10 wickets.

During the fifth T20I against Zimbabwe, Jaiswal started his innings from where he last left on Saturday and became the second player in the world to score two sixes on the first two balls of a T20I match.